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15-43x-6x^2=0
a = -6; b = -43; c = +15;
Δ = b2-4ac
Δ = -432-4·(-6)·15
Δ = 2209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2209}=47$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-47}{2*-6}=\frac{-4}{-12} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+47}{2*-6}=\frac{90}{-12} =-7+1/2 $
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